9617. Number of positive

Find the number of positive integers in the given array.

Input. The first line contains the number of integers n (1 ≤ n ≤ 100) in the array. The second line contains n integers, each with an absolute value not exceeding 100.

Output. Print the number of positive integers in the array.

Sample input	Sample output
5 -5 6 8 -3 0	2

SOLUTION

loops

Algorithm analysis

Declare a variable c to count the number of positive numbers in the array. Initially, assign it the value c = 0. Then, iterate through all the input numbers and increment c by 1 for each positive number.

Algorithm implementation

Declare an array.

int m[101];

Read the input data.

scanf("%d", &n);

for (i = 0; i < n; i++)

scanf("%d", &m[i]);

Count the number of positive integers in the variable c.

c = 0;

for (i = 0; i < n; i++)

if (m[i] > 0) c++;

Print the answer.

printf("%d\n", c);

Java implementation

import java.util.*;

class Main

{

public static void main(String[] args)

{

Scanner con = new Scanner(System.in);

int n = con.nextInt();

int c = 0;

for(int i = 0; i < n; i++)

{

int val = con.nextInt();

if (val > 0) c++;

}

System.out.println(c);

con.close();

}

}

Python implementation

Read the input data.

n = int(input())

lst = list(map(int, input().split()))

Count the number of positive integers in the variable c.

c = 0

for i in range(n):

if lst[i] > 0: c += 1

Print the answer.

print(c)

Python implementation – list

Read the input data.

n = int(input())

lst = list(map(int, input().split()))

Create a list p that contains only positive integers.

p = [x for x in lst if x > 0]

The length of the list p equals the count of positive integers.

res = len(p)

Print the answer.

print(res)